101113301134303 has 4 divisors (see below), whose sum is σ = 102249405641520. Its totient is φ = 99977196627088.

The previous prime is 101113301134297. The next prime is 101113301134331. The reversal of 101113301134303 is 303431103311101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101113301134303 - 2⁵ = 101113301134271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101113301134103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 568052253475 + ... + 568052253652.

It is an arithmetic number, because the mean of its divisors is an integer number (25562351410380).

Almost surely, 2^{101113301134303} is an apocalyptic number.

101113301134303 is a deficient number, since it is larger than the sum of its proper divisors (1136104507217).

101113301134303 is an equidigital number, since it uses as much as digits as its factorization.

101113301134303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1136104507216.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 101113301134303 its reverse (303431103311101), we get a palindrome (404544404445404).

The spelling of 101113301134303 in words is "one hundred one trillion, one hundred thirteen billion, three hundred one million, one hundred thirty-four thousand, three hundred three".