Base | Representation |
---|---|
bin | 10010110101010111… |
… | …01010110001111101 |
3 | 222002200020212011112 |
4 | 21122223222301331 |
5 | 131202000101303 |
6 | 4351200531405 |
7 | 505365620306 |
oct | 113253526175 |
9 | 28080225145 |
10 | 10111331453 |
11 | 4319645a83 |
12 | 1b62320b65 |
13 | c51a9a882 |
14 | 6bcc637ad |
15 | 3e2a500d8 |
hex | 25aaeac7d |
10111331453 has 2 divisors, whose sum is σ = 10111331454. Its totient is φ = 10111331452.
The previous prime is 10111331341. The next prime is 10111331459. The reversal of 10111331453 is 35413311101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9628123129 + 483208324 = 98123^2 + 21982^2 .
It is a cyclic number.
It is not a de Polignac number, because 10111331453 - 212 = 10111327357 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10111331459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055665726 + 5055665727.
It is an arithmetic number, because the mean of its divisors is an integer number (5055665727).
Almost surely, 210111331453 is an apocalyptic number.
It is an amenable number.
10111331453 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111331453 is an equidigital number, since it uses as much as digits as its factorization.
10111331453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 10111331453 its reverse (35413311101), we get a palindrome (45524642554).
The spelling of 10111331453 in words is "ten billion, one hundred eleven million, three hundred thirty-one thousand, four hundred fifty-three".
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