Base | Representation |
---|---|
bin | 1001001100100011111100… |
… | …0100110010000011111111 |
3 | 1022210122022122010021222012 |
4 | 2103020333010302003333 |
5 | 2311131132233424043 |
6 | 33301041310241435 |
7 | 2062345124243612 |
oct | 223107704620377 |
9 | 38718278107865 |
10 | 10111411233023 |
11 | 3249253045411 |
12 | 11737ab1b627b |
13 | 58466ab37a49 |
14 | 26d57590a179 |
15 | 12804ad9da18 |
hex | 9323f1320ff |
10111411233023 has 2 divisors, whose sum is σ = 10111411233024. Its totient is φ = 10111411233022.
The previous prime is 10111411232953. The next prime is 10111411233031. The reversal of 10111411233023 is 32033211411101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10111411233023 - 212 = 10111411228927 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10111411233023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10111411233043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055705616511 + 5055705616512.
It is an arithmetic number, because the mean of its divisors is an integer number (5055705616512).
Almost surely, 210111411233023 is an apocalyptic number.
10111411233023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111411233023 is an equidigital number, since it uses as much as digits as its factorization.
10111411233023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 10111411233023 its reverse (32033211411101), we get a palindrome (42144622644124).
The spelling of 10111411233023 in words is "ten trillion, one hundred eleven billion, four hundred eleven million, two hundred thirty-three thousand, twenty-three".
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