1011200011141 has 2 divisors, whose sum is σ = 1011200011142. Its totient is φ = 1011200011140.

The previous prime is 1011200011121. The next prime is 1011200011201. The reversal of 1011200011141 is 1411100021101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 620543760516 + 390656250625 = 787746^2 + 625025^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011200011141 - 2¹¹ = 1011200009093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011200011111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600005570 + 505600005571.

It is an arithmetic number, because the mean of its divisors is an integer number (505600005571).

Almost surely, 2^{1011200011141} is an apocalyptic number.

It is an amenable number.

1011200011141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200011141 is an equidigital number, since it uses as much as digits as its factorization.

1011200011141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1011200011141 its reverse (1411100021101), we get a palindrome (2422300032242).

The spelling of 1011200011141 in words is "one trillion, eleven billion, two hundred million, eleven thousand, one hundred forty-one".