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1011200117 is a prime number
BaseRepresentation
bin111100010001011…
…011000001110101
32121110202021210012
4330101123001311
54032331400432
6244201310005
734026026204
oct7421330165
92543667705
101011200117
11479883684
12242795305
1313165c085
149842523b
155db94cb2
hex3c45b075

1011200117 has 2 divisors, whose sum is σ = 1011200118. Its totient is φ = 1011200116.

The previous prime is 1011200087. The next prime is 1011200123. The reversal of 1011200117 is 7110021101.

1011200117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1011176401 + 23716 = 31799^2 + 154^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011200117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011200317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600058 + 505600059.

It is an arithmetic number, because the mean of its divisors is an integer number (505600059).

Almost surely, 21011200117 is an apocalyptic number.

It is an amenable number.

1011200117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200117 is an equidigital number, since it uses as much as digits as its factorization.

1011200117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 14.

The square root of 1011200117 is about 31799.3729026218. The cubic root of 1011200117 is about 1003.7195203487.

Adding to 1011200117 its reverse (7110021101), we get a palindrome (8121221218).

The spelling of 1011200117 in words is "one billion, eleven million, two hundred thousand, one hundred seventeen".