1011200119999 has 2 divisors, whose sum is σ = 1011200120000. Its totient is φ = 1011200119998.

The previous prime is 1011200119939. The next prime is 1011200120009. The reversal of 1011200119999 is 9999110021101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011200119999 - 2¹⁷ = 1011199988927 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011200119939) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600059999 + 505600060000.

It is an arithmetic number, because the mean of its divisors is an integer number (505600060000).

Almost surely, 2^{1011200119999} is an apocalyptic number.

1011200119999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200119999 is an equidigital number, since it uses as much as digits as its factorization.

1011200119999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 43.

The spelling of 1011200119999 in words is "one trillion, eleven billion, two hundred million, one hundred nineteen thousand, nine hundred ninety-nine".