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10112001303311 is a prime number
BaseRepresentation
bin1001001100100110001000…
…1111101110001100001111
31022210200211202102222020022
42103021202033232030033
52311133334313201221
633301220025412355
72062365550615265
oct223114217561417
938720752388208
1010112001303311
113249526130a06
12117393493a0bb
13584733167a6b
1426d5d002a435
15128082aa94ab
hex932623ee30f

10112001303311 has 2 divisors, whose sum is σ = 10112001303312. Its totient is φ = 10112001303310.

The previous prime is 10112001303293. The next prime is 10112001303319. The reversal of 10112001303311 is 11330310021101.

10112001303311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10112001303311 - 218 = 10112001041167 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10112001303311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112001303319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056000651655 + 5056000651656.

It is an arithmetic number, because the mean of its divisors is an integer number (5056000651656).

Almost surely, 210112001303311 is an apocalyptic number.

10112001303311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112001303311 is an equidigital number, since it uses as much as digits as its factorization.

10112001303311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10112001303311 its reverse (11330310021101), we get a palindrome (21442311324412).

The spelling of 10112001303311 in words is "ten trillion, one hundred twelve billion, one million, three hundred three thousand, three hundred eleven".