1011200209993 has 2 divisors, whose sum is σ = 1011200209994. Its totient is φ = 1011200209992.

The previous prime is 1011200209973. The next prime is 1011200210017. The reversal of 1011200209993 is 3999020021101.

It is a happy number.

1011200209993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 994431772944 + 16768437049 = 997212^2 + 129493^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011200209993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011200209963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600104996 + 505600104997.

It is an arithmetic number, because the mean of its divisors is an integer number (505600104997).

Almost surely, 2^{1011200209993} is an apocalyptic number.

It is an amenable number.

1011200209993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200209993 is an equidigital number, since it uses as much as digits as its factorization.

1011200209993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 37.

The spelling of 1011200209993 in words is "one trillion, eleven billion, two hundred million, two hundred nine thousand, nine hundred ninety-three".