Base | Representation |
---|---|
bin | 11101011011100000011… |
… | …10101110000000011100 |
3 | 10120200002021121121120220 |
4 | 32231300032232000130 |
5 | 113031414224034322 |
6 | 2052312230041340 |
7 | 133025325030126 |
oct | 16556016560034 |
9 | 3520067547526 |
10 | 1011200221212 |
11 | 35a936187965 |
12 | 143b88aa9250 |
13 | 7448182707c |
14 | 36d29b56216 |
15 | 1b484ba555c |
hex | eb703ae01c |
1011200221212 has 48 divisors (see below), whose sum is σ = 2381075208960. Its totient is φ = 333981704448.
The previous prime is 1011200221183. The next prime is 1011200221249. The reversal of 1011200221212 is 2121220021101.
It is a junction number, because it is equal to n+sod(n) for n = 1011200221191 and 1011200221200.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4388223 + ... + 4612905.
It is an arithmetic number, because the mean of its divisors is an integer number (49605733520).
Almost surely, 21011200221212 is an apocalyptic number.
1011200221212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1011200221212 is an abundant number, since it is smaller than the sum of its proper divisors (1369874987748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011200221212 is a wasteful number, since it uses less digits than its factorization.
1011200221212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 228122 (or 228120 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 1011200221212 its reverse (2121220021101), we get a palindrome (3132420242313).
The spelling of 1011200221212 in words is "one trillion, eleven billion, two hundred million, two hundred twenty-one thousand, two hundred twelve".
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