Base | Representation |
---|---|
bin | 10110111111011111011100… |
… | …010111100000100100101011 |
3 | 111021000222200111000220200222 |
4 | 112333133130113200210223 |
5 | 101223222442210344404 |
6 | 555021534354320255 |
7 | 30204454434560315 |
oct | 2677373427404453 |
9 | 437028614026628 |
10 | 101120112199979 |
11 | 2a246887160744 |
12 | b411908b8908b |
13 | 445677c921662 |
14 | 1ad834d44a7b5 |
15 | ba5575ca0dbe |
hex | 5bf7dc5e092b |
101120112199979 has 2 divisors, whose sum is σ = 101120112199980. Its totient is φ = 101120112199978.
The previous prime is 101120112199973. The next prime is 101120112200147. The reversal of 101120112199979 is 979991211021101.
It is a weak prime.
It is an emirp because it is prime and its reverse (979991211021101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101120112199979 - 224 = 101120095422763 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101120112199979.
It is not a weakly prime, because it can be changed into another prime (101120112199973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560056099989 + 50560056099990.
It is an arithmetic number, because the mean of its divisors is an integer number (50560056099990).
Almost surely, 2101120112199979 is an apocalyptic number.
101120112199979 is a deficient number, since it is larger than the sum of its proper divisors (1).
101120112199979 is an equidigital number, since it uses as much as digits as its factorization.
101120112199979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 53.
The spelling of 101120112199979 in words is "one hundred one trillion, one hundred twenty billion, one hundred twelve million, one hundred ninety-nine thousand, nine hundred seventy-nine".
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