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101120130022 = 250560065011
BaseRepresentation
bin101111000101100111…
…0101011101111100110
3100200000020100211202211
41132023032223233212
53124043223130042
6114242015154034
710206564631462
oct1361316535746
9320006324684
10101120130022
113998074a39a
1217720b1591a
1396c68baa82
144c73b1d4a2
15296c74a017
hex178b3abbe6

101120130022 has 4 divisors (see below), whose sum is σ = 151680195036. Its totient is φ = 50560065010.

The previous prime is 101120129923. The next prime is 101120130029. The reversal of 101120130022 is 220031021101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 220031021101 = 863254960627.

It is a junction number, because it is equal to n+sod(n) for n = 101120129984 and 101120130011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101120130029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25280032504 + ... + 25280032507.

It is an arithmetic number, because the mean of its divisors is an integer number (37920048759).

Almost surely, 2101120130022 is an apocalyptic number.

101120130022 is a deficient number, since it is larger than the sum of its proper divisors (50560065014).

101120130022 is an equidigital number, since it uses as much as digits as its factorization.

101120130022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50560065013.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 101120130022 its reverse (220031021101), we get a palindrome (321151151123).

The spelling of 101120130022 in words is "one hundred one billion, one hundred twenty million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 50560065011 101120130022