10112019838957 has 2 divisors, whose sum is σ = 10112019838958. Its totient is φ = 10112019838956.

The previous prime is 10112019838933. The next prime is 10112019838961. The reversal of 10112019838957 is 75983891021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8812194109156 + 1299825729801 = 2968534^2 + 1140099^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112019838957 - 2³¹ = 10109872355309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112019838898 and 10112019838907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112019838997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056009919478 + 5056009919479.

It is an arithmetic number, because the mean of its divisors is an integer number (5056009919479).

Almost surely, 2^{10112019838957} is an apocalyptic number.

It is an amenable number.

10112019838957 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112019838957 is an equidigital number, since it uses as much as digits as its factorization.

10112019838957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 55.

The spelling of 10112019838957 in words is "ten trillion, one hundred twelve billion, nineteen million, eight hundred thirty-eight thousand, nine hundred fifty-seven".