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10112043122407 is a prime number
BaseRepresentation
bin1001001100100110010010…
…1111001111111011100111
31022210200221200010121020201
42103021210233033323213
52311133431014404112
633301224122011331
72062366566230662
oct223114457177347
938720850117221
1010112043122407
1132495477a4246
121173946946b47
1358473ba1a5a5
1426d5d57d46d9
151280865ba257
hex93264bcfee7

10112043122407 has 2 divisors, whose sum is σ = 10112043122408. Its totient is φ = 10112043122406.

The previous prime is 10112043122329. The next prime is 10112043122413. The reversal of 10112043122407 is 70422134021101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10112043122407 - 211 = 10112043120359 is a prime.

It is a super-2 number, since 2×101120431224072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112043126407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056021561203 + 5056021561204.

It is an arithmetic number, because the mean of its divisors is an integer number (5056021561204).

Almost surely, 210112043122407 is an apocalyptic number.

10112043122407 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112043122407 is an equidigital number, since it uses as much as digits as its factorization.

10112043122407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 10112043122407 its reverse (70422134021101), we get a palindrome (80534177143508).

The spelling of 10112043122407 in words is "ten trillion, one hundred twelve billion, forty-three million, one hundred twenty-two thousand, four hundred seven".