Base | Representation |
---|---|
bin | 1001001100100110010010… |
… | …1111001111111011100111 |
3 | 1022210200221200010121020201 |
4 | 2103021210233033323213 |
5 | 2311133431014404112 |
6 | 33301224122011331 |
7 | 2062366566230662 |
oct | 223114457177347 |
9 | 38720850117221 |
10 | 10112043122407 |
11 | 32495477a4246 |
12 | 1173946946b47 |
13 | 58473ba1a5a5 |
14 | 26d5d57d46d9 |
15 | 1280865ba257 |
hex | 93264bcfee7 |
10112043122407 has 2 divisors, whose sum is σ = 10112043122408. Its totient is φ = 10112043122406.
The previous prime is 10112043122329. The next prime is 10112043122413. The reversal of 10112043122407 is 70422134021101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10112043122407 - 211 = 10112043120359 is a prime.
It is a super-2 number, since 2×101120431224072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112043126407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056021561203 + 5056021561204.
It is an arithmetic number, because the mean of its divisors is an integer number (5056021561204).
Almost surely, 210112043122407 is an apocalyptic number.
10112043122407 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112043122407 is an equidigital number, since it uses as much as digits as its factorization.
10112043122407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 10112043122407 its reverse (70422134021101), we get a palindrome (80534177143508).
The spelling of 10112043122407 in words is "ten trillion, one hundred twelve billion, forty-three million, one hundred twenty-two thousand, four hundred seven".
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