Base | Representation |
---|---|
bin | 10110111111100000011000… |
… | …100000100010110000111101 |
3 | 111021001002021210122111012001 |
4 | 112333200120200202300331 |
5 | 101223232024011414323 |
6 | 555022222440542301 |
7 | 30204521436131011 |
oct | 2677403040426075 |
9 | 437032253574161 |
10 | 101121121201213 |
11 | 2a247254772263 |
12 | b411b4aa81991 |
13 | 44568b09908c9 |
14 | 1ad840745c541 |
15 | ba55d465e3ad |
hex | 5bf818822c3d |
101121121201213 has 2 divisors, whose sum is σ = 101121121201214. Its totient is φ = 101121121201212.
The previous prime is 101121121201063. The next prime is 101121121201237. The reversal of 101121121201213 is 312102121121101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99832809939769 + 1288311261444 = 9991637^2 + 1135038^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101121121201213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101121121201283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560560600606 + 50560560600607.
It is an arithmetic number, because the mean of its divisors is an integer number (50560560600607).
Almost surely, 2101121121201213 is an apocalyptic number.
It is an amenable number.
101121121201213 is a deficient number, since it is larger than the sum of its proper divisors (1).
101121121201213 is an equidigital number, since it uses as much as digits as its factorization.
101121121201213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 101121121201213 its reverse (312102121121101), we get a palindrome (413223242322314).
The spelling of 101121121201213 in words is "one hundred one trillion, one hundred twenty-one billion, one hundred twenty-one million, two hundred one thousand, two hundred thirteen".
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