10112112419 has 2 divisors, whose sum is σ = 10112112420. Its totient is φ = 10112112418.

The previous prime is 10112112407. The next prime is 10112112421. The reversal of 10112112419 is 91421121101.

It is a strong prime.

It is an emirp because it is prime and its reverse (91421121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112112419 - 2¹² = 10112108323 is a prime.

It is a super-2 number, since 2×10112112419² (a number of 21 digits) contains 22 as substring.

Together with 10112112421, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112112394 and 10112112403.

It is not a weakly prime, because it can be changed into another prime (10112112919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056056209 + 5056056210.

It is an arithmetic number, because the mean of its divisors is an integer number (5056056210).

Almost surely, 2^10112112419 is an apocalyptic number.

10112112419 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112112419 is an equidigital number, since it uses as much as digits as its factorization.

10112112419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 23.

The spelling of 10112112419 in words is "ten billion, one hundred twelve million, one hundred twelve thousand, four hundred nineteen".