101121201211907 has 2 divisors, whose sum is σ = 101121201211908. Its totient is φ = 101121201211906.

The previous prime is 101121201211879. The next prime is 101121201211909. The reversal of 101121201211907 is 709112102121101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101121201211907 is a prime.

Together with 101121201211909, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101121201211907.

It is not a weakly prime, because it can be changed into another prime (101121201211909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560600605953 + 50560600605954.

It is an arithmetic number, because the mean of its divisors is an integer number (50560600605954).

Almost surely, 2^{101121201211907} is an apocalyptic number.

101121201211907 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121201211907 is an equidigital number, since it uses as much as digits as its factorization.

101121201211907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 29.

The spelling of 101121201211907 in words is "one hundred one trillion, one hundred twenty-one billion, two hundred one million, two hundred eleven thousand, nine hundred seven".