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101121311413 is a prime number
BaseRepresentation
bin101111000101101001…
…1001100001010110101
3100200000022120212100001
41132023103030022311
53124044023431123
6114242100351301
710206610651663
oct1361323141265
9320008525301
10101121311413
1139981386a51
12177213a5531
1396c6c12715
144c73d49c33
15296c8d00ad
hex178b4cc2b5

101121311413 has 2 divisors, whose sum is σ = 101121311414. Its totient is φ = 101121311412.

The previous prime is 101121311383. The next prime is 101121311441. The reversal of 101121311413 is 314113121101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51384729124 + 49736582289 = 226682^2 + 223017^2 .

It is a cyclic number.

It is not a de Polignac number, because 101121311413 - 213 = 101121303221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101121311443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560655706 + 50560655707.

It is an arithmetic number, because the mean of its divisors is an integer number (50560655707).

Almost surely, 2101121311413 is an apocalyptic number.

It is an amenable number.

101121311413 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121311413 is an equidigital number, since it uses as much as digits as its factorization.

101121311413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 101121311413 its reverse (314113121101), we get a palindrome (415234432514).

The spelling of 101121311413 in words is "one hundred one billion, one hundred twenty-one million, three hundred eleven thousand, four hundred thirteen".