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1011214343533 is a prime number
BaseRepresentation
bin11101011011100010001…
…00100101110101101101
310120200010021012002202211
432231301010211311231
5113031431332443113
62052313452450421
7133025556046102
oct16556104456555
93520107162684
101011214343533
1135a9431531a9
12143b91779a11
1374484730084
1436d2b990aa9
151b486044b3d
hexeb71125d6d

1011214343533 has 2 divisors, whose sum is σ = 1011214343534. Its totient is φ = 1011214343532.

The previous prime is 1011214343521. The next prime is 1011214343539. The reversal of 1011214343533 is 3353434121101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 725805171364 + 285409172169 = 851942^2 + 534237^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011214343533 - 217 = 1011214212461 is a prime.

It is a super-2 number, since 2×10112143435332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011214343495 and 1011214343504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011214343539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505607171766 + 505607171767.

It is an arithmetic number, because the mean of its divisors is an integer number (505607171767).

Almost surely, 21011214343533 is an apocalyptic number.

It is an amenable number.

1011214343533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011214343533 is an equidigital number, since it uses as much as digits as its factorization.

1011214343533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1011214343533 its reverse (3353434121101), we get a palindrome (4364648464634).

The spelling of 1011214343533 in words is "one trillion, eleven billion, two hundred fourteen million, three hundred forty-three thousand, five hundred thirty-three".