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101122100083 is a prime number
BaseRepresentation
bin101111000101101011…
…0001100101101110011
3100200000101001221012001
41132023112030231303
53124044224200313
6114242125314431
710206620445214
oct1361326145563
9320011057161
10101122100083
1139981875544
1217721705a17
1396c712a6a4
144c740b340b
15296c9d8add
hex178b58cb73

101122100083 has 2 divisors, whose sum is σ = 101122100084. Its totient is φ = 101122100082.

The previous prime is 101122100063. The next prime is 101122100087. The reversal of 101122100083 is 380001221101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101122100083 - 221 = 101120002931 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101122100083.

It is not a weakly prime, because it can be changed into another prime (101122100087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561050041 + 50561050042.

It is an arithmetic number, because the mean of its divisors is an integer number (50561050042).

Almost surely, 2101122100083 is an apocalyptic number.

101122100083 is a deficient number, since it is larger than the sum of its proper divisors (1).

101122100083 is an equidigital number, since it uses as much as digits as its factorization.

101122100083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 101122100083 its reverse (380001221101), we get a palindrome (481123321184).

The spelling of 101122100083 in words is "one hundred one billion, one hundred twenty-two million, one hundred thousand, eighty-three".