101122100117 has 2 divisors, whose sum is σ = 101122100118. Its totient is φ = 101122100116.

The previous prime is 101122100113. The next prime is 101122100129. The reversal of 101122100117 is 711001221101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101026079716 + 96020401 = 317846^2 + 9799^2 .

It is an emirp because it is prime and its reverse (711001221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101122100117 - 2² = 101122100113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101122100095 and 101122100104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101122100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561050058 + 50561050059.

It is an arithmetic number, because the mean of its divisors is an integer number (50561050059).

Almost surely, 2^101122100117 is an apocalyptic number.

It is an amenable number.

101122100117 is a deficient number, since it is larger than the sum of its proper divisors (1).

101122100117 is an equidigital number, since it uses as much as digits as its factorization.

101122100117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 101122100117 its reverse (711001221101), we get a palindrome (812123321218).

The spelling of 101122100117 in words is "one hundred one billion, one hundred twenty-two million, one hundred thousand, one hundred seventeen".