10112210083 has 2 divisors, whose sum is σ = 10112210084. Its totient is φ = 10112210082.

The previous prime is 10112210063. The next prime is 10112210089. The reversal of 10112210083 is 38001221101.

It is a strong prime.

It is an emirp because it is prime and its reverse (38001221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112210083 - 2⁵ = 10112210051 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10112210083.

It is not a weakly prime, because it can be changed into another prime (10112210089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056105041 + 5056105042.

It is an arithmetic number, because the mean of its divisors is an integer number (5056105042).

Almost surely, 2^10112210083 is an apocalyptic number.

10112210083 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112210083 is an equidigital number, since it uses as much as digits as its factorization.

10112210083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 10112210083 its reverse (38001221101), we get a palindrome (48113431184).

The spelling of 10112210083 in words is "ten billion, one hundred twelve million, two hundred ten thousand, eighty-three".