Base | Representation |
---|---|
bin | 10110111111100001010100… |
… | …000010101010001001011011 |
3 | 111021001011212102001201200002 |
4 | 112333201110002222021123 |
5 | 101223241100210000331 |
6 | 555022505520403215 |
7 | 30204555254600051 |
oct | 2677412402521133 |
9 | 437034772051602 |
10 | 101122120000091 |
11 | 2a247717545683 |
12 | b41218947650b |
13 | 4456a0c89a168 |
14 | 1ad849dd761d1 |
15 | ba56421a49cb |
hex | 5bf8540aa25b |
101122120000091 has 2 divisors, whose sum is σ = 101122120000092. Its totient is φ = 101122120000090.
The previous prime is 101122120000063. The next prime is 101122120000141. The reversal of 101122120000091 is 190000021221101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101122120000091 - 214 = 101122119983707 is a prime.
It is not a weakly prime, because it can be changed into another prime (101122120000061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561060000045 + 50561060000046.
It is an arithmetic number, because the mean of its divisors is an integer number (50561060000046).
Almost surely, 2101122120000091 is an apocalyptic number.
101122120000091 is a deficient number, since it is larger than the sum of its proper divisors (1).
101122120000091 is an equidigital number, since it uses as much as digits as its factorization.
101122120000091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 101122120000091 its reverse (190000021221101), we get a palindrome (291122141221192).
The spelling of 101122120000091 in words is "one hundred one trillion, one hundred twenty-two billion, one hundred twenty million, ninety-one", and thus it is an aban number.
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