101122120000141 has 2 divisors, whose sum is σ = 101122120000142. Its totient is φ = 101122120000140.

The previous prime is 101122120000091. The next prime is 101122120000157. The reversal of 101122120000141 is 141000021221101.

It is an a-pointer prime, because the next prime (101122120000157) can be obtained adding 101122120000141 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93729409146025 + 7392710854116 = 9681395^2 + 2718954^2 .

It is a cyclic number.

It is not a de Polignac number, because 101122120000141 - 2³⁹ = 100572364186253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101122120000171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561060000070 + 50561060000071.

It is an arithmetic number, because the mean of its divisors is an integer number (50561060000071).

Almost surely, 2^{101122120000141} is an apocalyptic number.

It is an amenable number.

101122120000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

101122120000141 is an equidigital number, since it uses as much as digits as its factorization.

101122120000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 101122120000141 its reverse (141000021221101), we get a palindrome (242122141221242).

The spelling of 101122120000141 in words is "one hundred one trillion, one hundred twenty-two billion, one hundred twenty million, one hundred forty-one", and thus it is an aban number.