Base | Representation |
---|---|
bin | 10010110101011110… |
… | …00011111111011111 |
3 | 222002201221001121022 |
4 | 21122233003333133 |
5 | 131202212034101 |
6 | 4351231554355 |
7 | 505406314214 |
oct | 113257037737 |
9 | 28081831538 |
10 | 10112221151 |
11 | 431a0a346a |
12 | 1b6268b9bb |
13 | c5201c816 |
14 | 6bd015b0b |
15 | 3e2b78a1b |
hex | 25abc3fdf |
10112221151 has 2 divisors, whose sum is σ = 10112221152. Its totient is φ = 10112221150.
The previous prime is 10112221039. The next prime is 10112221169. The reversal of 10112221151 is 15112221101.
It is a strong prime.
It is an emirp because it is prime and its reverse (15112221101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10112221151 - 230 = 9038479327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112224151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056110575 + 5056110576.
It is an arithmetic number, because the mean of its divisors is an integer number (5056110576).
Almost surely, 210112221151 is an apocalyptic number.
10112221151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112221151 is an equidigital number, since it uses as much as digits as its factorization.
10112221151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 10112221151 its reverse (15112221101), we get a palindrome (25224442252).
The spelling of 10112221151 in words is "ten billion, one hundred twelve million, two hundred twenty-one thousand, one hundred fifty-one".
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