Base | Representation |
---|---|
bin | 11101011011100100000… |
… | …00101100111001110111 |
3 | 10120200011100211200002211 |
4 | 32231302000230321313 |
5 | 113031444401213421 |
6 | 2052315214314251 |
7 | 133026140015416 |
oct | 16556200547167 |
9 | 3520140750084 |
10 | 1011230101111 |
11 | 35a95103609a |
12 | 143b96ab8987 |
13 | 74487a89499 |
14 | 36d2dad347d |
15 | 1b4876089e1 |
hex | eb7202ce77 |
1011230101111 has 2 divisors, whose sum is σ = 1011230101112. Its totient is φ = 1011230101110.
The previous prime is 1011230101073. The next prime is 1011230101117. The reversal of 1011230101111 is 1111010321101.
It is a strong prime.
It is an emirp because it is prime and its reverse (1111010321101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1011230101111 - 213 = 1011230092919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011230101091 and 1011230101100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011230101117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505615050555 + 505615050556.
It is an arithmetic number, because the mean of its divisors is an integer number (505615050556).
Almost surely, 21011230101111 is an apocalyptic number.
1011230101111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011230101111 is an equidigital number, since it uses as much as digits as its factorization.
1011230101111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 1011230101111 its reverse (1111010321101), we get a palindrome (2122240422212).
The spelling of 1011230101111 in words is "one trillion, eleven billion, two hundred thirty million, one hundred one thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •