Search a number
-
+
10112312137 is a prime number
BaseRepresentation
bin10010110101011110…
…11010001101001001
3222002202002200102011
421122233122031021
5131202222442022
64351233535521
7505410143404
oct113257321511
928082080364
1010112312137
11431a155864
121b627145a1
13c52052065
146bd03ad3b
153e2b95977
hex25abda349

10112312137 has 2 divisors, whose sum is σ = 10112312138. Its totient is φ = 10112312136.

The previous prime is 10112312131. The next prime is 10112312141. The reversal of 10112312137 is 73121321101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10100451001 + 11861136 = 100501^2 + 3444^2 .

It is an emirp because it is prime and its reverse (73121321101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10112312137 is a prime.

It is a super-2 number, since 2×101123121372 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10112312131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056156068 + 5056156069.

It is an arithmetic number, because the mean of its divisors is an integer number (5056156069).

Almost surely, 210112312137 is an apocalyptic number.

It is an amenable number.

10112312137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112312137 is an equidigital number, since it uses as much as digits as its factorization.

10112312137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 10112312137 its reverse (73121321101), we get a palindrome (83233633238).

The spelling of 10112312137 in words is "ten billion, one hundred twelve million, three hundred twelve thousand, one hundred thirty-seven".