Base | Representation |
---|---|
bin | 10010110101011110… |
… | …11010001101000011 |
3 | 222002202002200101221 |
4 | 21122233122031003 |
5 | 131202222442011 |
6 | 4351233535511 |
7 | 505410143365 |
oct | 113257321503 |
9 | 28082080357 |
10 | 10112312131 |
11 | 431a155859 |
12 | 1b62714597 |
13 | c5205205c |
14 | 6bd03ad35 |
15 | 3e2b95971 |
hex | 25abda343 |
10112312131 has 2 divisors, whose sum is σ = 10112312132. Its totient is φ = 10112312130.
The previous prime is 10112312123. The next prime is 10112312137. The reversal of 10112312131 is 13121321101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10112312131 - 23 = 10112312123 is a prime.
It is a super-2 number, since 2×101123121312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10112312137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056156065 + 5056156066.
It is an arithmetic number, because the mean of its divisors is an integer number (5056156066).
Almost surely, 210112312131 is an apocalyptic number.
10112312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112312131 is an equidigital number, since it uses as much as digits as its factorization.
10112312131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 10112312131 its reverse (13121321101), we get a palindrome (23233633232).
The spelling of 10112312131 in words is "ten billion, one hundred twelve million, three hundred twelve thousand, one hundred thirty-one".
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