1011231300020 has 12 divisors (see below), whose sum is σ = 2123585730084. Its totient is φ = 404492520000.

The previous prime is 1011231299993. The next prime is 1011231300043. The reversal of 1011231300020 is 200031321101.

1011231300020 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 611167459984 + 400063840036 = 781772^2 + 632506^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1011231299968 and 1011231300004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25280782481 + ... + 25280782520.

It is an arithmetic number, because the mean of its divisors is an integer number (176965477507).

Almost surely, 2^{1011231300020} is an apocalyptic number.

1011231300020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1011231300020 is an abundant number, since it is smaller than the sum of its proper divisors (1112354430064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011231300020 is a wasteful number, since it uses less digits than its factorization.

1011231300020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50561565010 (or 50561565008 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1011231300020 its reverse (200031321101), we get a palindrome (1211262621121).

The spelling of 1011231300020 in words is "one trillion, eleven billion, two hundred thirty-one million, three hundred thousand, twenty".