10112340413191 has 2 divisors, whose sum is σ = 10112340413192. Its totient is φ = 10112340413190.

The previous prime is 10112340413101. The next prime is 10112340413261. The reversal of 10112340413191 is 19131404321101.

10112340413191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10112340413191 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112340413101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056170206595 + 5056170206596.

It is an arithmetic number, because the mean of its divisors is an integer number (5056170206596).

Almost surely, 2^{10112340413191} is an apocalyptic number.

10112340413191 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112340413191 is an equidigital number, since it uses as much as digits as its factorization.

10112340413191 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 31.

Adding to 10112340413191 its reverse (19131404321101), we get a palindrome (29243744734292).

The spelling of 10112340413191 in words is "ten trillion, one hundred twelve billion, three hundred forty million, four hundred thirteen thousand, one hundred ninety-one".