101123411531 has 2 divisors, whose sum is σ = 101123411532. Its totient is φ = 101123411530.

The previous prime is 101123411503. The next prime is 101123411533. The reversal of 101123411531 is 135114321101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101123411531 - 2²⁶ = 101056302667 is a prime.

It is a super-2 number, since 2×101123411531² (a number of 23 digits) contains 22 as substring.

Together with 101123411533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101123411497 and 101123411506.

It is not a weakly prime, because it can be changed into another prime (101123411533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561705765 + 50561705766.

It is an arithmetic number, because the mean of its divisors is an integer number (50561705766).

Almost surely, 2^101123411531 is an apocalyptic number.

101123411531 is a deficient number, since it is larger than the sum of its proper divisors (1).

101123411531 is an equidigital number, since it uses as much as digits as its factorization.

101123411531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 101123411531 its reverse (135114321101), we get a palindrome (236237732632).

The spelling of 101123411531 in words is "one hundred one billion, one hundred twenty-three million, four hundred eleven thousand, five hundred thirty-one".