1011300113020 has 12 divisors (see below), whose sum is σ = 2123730237384. Its totient is φ = 404520045200.

The previous prime is 1011300113011. The next prime is 1011300113051. The reversal of 1011300113020 is 203110031101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25282502806 + ... + 25282502845.

It is an arithmetic number, because the mean of its divisors is an integer number (176977519782).

Almost surely, 2^{1011300113020} is an apocalyptic number.

1011300113020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1011300113020 is an abundant number, since it is smaller than the sum of its proper divisors (1112430124364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011300113020 is a wasteful number, since it uses less digits than its factorization.

1011300113020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50565005660 (or 50565005658 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1011300113020 its reverse (203110031101), we get a palindrome (1214410144121).

The spelling of 1011300113020 in words is "one trillion, eleven billion, three hundred million, one hundred thirteen thousand, twenty".