10113001211 has 2 divisors, whose sum is σ = 10113001212. Its totient is φ = 10113001210.

The previous prime is 10113001201. The next prime is 10113001229. The reversal of 10113001211 is 11210031101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113001211 - 2⁶ = 10113001147 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10113001192 and 10113001201.

It is not a weakly prime, because it can be changed into another prime (10113001201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056500605 + 5056500606.

It is an arithmetic number, because the mean of its divisors is an integer number (5056500606).

Almost surely, 2^10113001211 is an apocalyptic number.

10113001211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113001211 is an equidigital number, since it uses as much as digits as its factorization.

10113001211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10113001211 its reverse (11210031101), we get a palindrome (21323032312).

The spelling of 10113001211 in words is "ten billion, one hundred thirteen million, one thousand, two hundred eleven".