Base | Representation |
---|---|
bin | 111100010001110… |
… | …011011100101110 |
3 | 2121110221100222211 |
4 | 330101303130232 |
5 | 4032343101032 |
6 | 244203401034 |
7 | 34026623626 |
oct | 7421633456 |
9 | 2543840884 |
10 | 1011300142 |
11 | 479941846 |
12 | 24282317a |
13 | 131695768 |
14 | 9844d886 |
15 | 5dbb4747 |
hex | 3c47372e |
1011300142 has 8 divisors (see below), whose sum is σ = 1517175000. Its totient is φ = 505575144.
The previous prime is 1011300119. The next prime is 1011300163. The reversal of 1011300142 is 2410031101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18717 + ... + 48712.
It is an arithmetic number, because the mean of its divisors is an integer number (189646875).
Almost surely, 21011300142 is an apocalyptic number.
1011300142 is a deficient number, since it is larger than the sum of its proper divisors (505874858).
1011300142 is an equidigital number, since it uses as much as digits as its factorization.
1011300142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74930.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1011300142 is about 31800.9456148713. The cubic root of 1011300142 is about 1003.7526142712.
Adding to 1011300142 its reverse (2410031101), we get a palindrome (3421331243).
The spelling of 1011300142 in words is "one billion, eleven million, three hundred thousand, one hundred forty-two".
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