1011300240022 has 4 divisors (see below), whose sum is σ = 1516950360036. Its totient is φ = 505650120010.

The previous prime is 1011300240007. The next prime is 1011300240023. The reversal of 1011300240022 is 2200420031101.

1011300240022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1011300239978 and 1011300240005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011300240023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252825060004 + ... + 252825060007.

It is an arithmetic number, because the mean of its divisors is an integer number (379237590009).

Almost surely, 2^{1011300240022} is an apocalyptic number.

1011300240022 is a deficient number, since it is larger than the sum of its proper divisors (505650120014).

1011300240022 is an equidigital number, since it uses as much as digits as its factorization.

1011300240022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505650120013.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1011300240022 its reverse (2200420031101), we get a palindrome (3211720271123).

The spelling of 1011300240022 in words is "one trillion, eleven billion, three hundred million, two hundred forty thousand, twenty-two".