10113012083 has 2 divisors, whose sum is σ = 10113012084. Its totient is φ = 10113012082.

The previous prime is 10113012047. The next prime is 10113012103. The reversal of 10113012083 is 38021031101.

It is an a-pointer prime, because the next prime (10113012103) can be obtained adding 10113012083 to its sum of digits (20).

It is a strong prime.

It is an emirp because it is prime and its reverse (38021031101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10113012083 - 2⁸ = 10113011827 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (10113012883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056506041 + 5056506042.

It is an arithmetic number, because the mean of its divisors is an integer number (5056506042).

Almost surely, 2^10113012083 is an apocalyptic number.

10113012083 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113012083 is an equidigital number, since it uses as much as digits as its factorization.

10113012083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10113012083 its reverse (38021031101), we get a palindrome (48134043184).

The spelling of 10113012083 in words is "ten billion, one hundred thirteen million, twelve thousand, eighty-three".