Base | Representation |
---|---|
bin | 10010110101100100… |
… | …00101000110100011 |
3 | 222002210102020121212 |
4 | 21122302011012203 |
5 | 131202412342011 |
6 | 4351300540335 |
7 | 505416120245 |
oct | 113262050643 |
9 | 28083366555 |
10 | 10113012131 |
11 | 431a593772 |
12 | 1b629b16ab |
13 | c52238861 |
14 | 6bd180095 |
15 | 3e2c8308b |
hex | 25ac851a3 |
10113012131 has 2 divisors, whose sum is σ = 10113012132. Its totient is φ = 10113012130.
The previous prime is 10113012103. The next prime is 10113012157. The reversal of 10113012131 is 13121031101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10113012131 - 210 = 10113011107 is a prime.
It is a super-2 number, since 2×101130121312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10113012031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056506065 + 5056506066.
It is an arithmetic number, because the mean of its divisors is an integer number (5056506066).
Almost surely, 210113012131 is an apocalyptic number.
10113012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113012131 is an equidigital number, since it uses as much as digits as its factorization.
10113012131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 10113012131 its reverse (13121031101), we get a palindrome (23234043232).
The spelling of 10113012131 in words is "ten billion, one hundred thirteen million, twelve thousand, one hundred thirty-one".
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