101130127664551 has 2 divisors, whose sum is σ = 101130127664552. Its totient is φ = 101130127664550.

The previous prime is 101130127664507. The next prime is 101130127664567. The reversal of 101130127664551 is 155466721031101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101130127664551 - 2⁹ = 101130127664039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101130127664498 and 101130127664507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101130127664591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565063832275 + 50565063832276.

It is an arithmetic number, because the mean of its divisors is an integer number (50565063832276).

Almost surely, 2^{101130127664551} is an apocalyptic number.

101130127664551 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130127664551 is an equidigital number, since it uses as much as digits as its factorization.

101130127664551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 43.

Adding to 101130127664551 its reverse (155466721031101), we get a palindrome (256596848695652).

The spelling of 101130127664551 in words is "one hundred one trillion, one hundred thirty billion, one hundred twenty-seven million, six hundred sixty-four thousand, five hundred fifty-one".