Base | Representation |
---|---|
bin | 10010110101100100… |
… | …01001101111011101 |
3 | 222002210110012200122 |
4 | 21122302021233131 |
5 | 131202413444013 |
6 | 4351301204325 |
7 | 505416226532 |
oct | 113262115735 |
9 | 28083405618 |
10 | 10113031133 |
11 | 431a5a6a77 |
12 | 1b62a006a5 |
13 | c522443ba |
14 | 6bd186d89 |
15 | 3e2c88a08 |
hex | 25ac89bdd |
10113031133 has 2 divisors, whose sum is σ = 10113031134. Its totient is φ = 10113031132.
The previous prime is 10113031091. The next prime is 10113031139. The reversal of 10113031133 is 33113031101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7130451364 + 2982579769 = 84442^2 + 54613^2 .
It is an emirp because it is prime and its reverse (33113031101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10113031133 - 212 = 10113027037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10113031139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056515566 + 5056515567.
It is an arithmetic number, because the mean of its divisors is an integer number (5056515567).
Almost surely, 210113031133 is an apocalyptic number.
It is an amenable number.
10113031133 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113031133 is an equidigital number, since it uses as much as digits as its factorization.
10113031133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 10113031133 its reverse (33113031101), we get a palindrome (43226062234).
The spelling of 10113031133 in words is "ten billion, one hundred thirteen million, thirty-one thousand, one hundred thirty-three".
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