101130332131 has 2 divisors, whose sum is σ = 101130332132. Its totient is φ = 101130332130.

The previous prime is 101130332113. The next prime is 101130332167. The reversal of 101130332131 is 131233031101.

Together with previous prime (101130332113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (131233031101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101130332131 - 2¹¹ = 101130330083 is a prime.

It is a super-2 number, since 2×101130332131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101130332099 and 101130332108.

It is not a weakly prime, because it can be changed into another prime (101130332101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565166065 + 50565166066.

It is an arithmetic number, because the mean of its divisors is an integer number (50565166066).

Almost surely, 2^101130332131 is an apocalyptic number.

101130332131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130332131 is an equidigital number, since it uses as much as digits as its factorization.

101130332131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 101130332131 its reverse (131233031101), we get a palindrome (232363363232).

The spelling of 101130332131 in words is "one hundred one billion, one hundred thirty million, three hundred thirty-two thousand, one hundred thirty-one".