101130332113 has 2 divisors, whose sum is σ = 101130332114. Its totient is φ = 101130332112.

The previous prime is 101130332111. The next prime is 101130332131. The reversal of 101130332113 is 311233031101.

Together with next prime (101130332131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61440528384 + 39689803729 = 247872^2 + 199223^2 .

It is a cyclic number.

It is not a de Polignac number, because 101130332113 - 2¹ = 101130332111 is a prime.

Together with 101130332111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (101130332111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565166056 + 50565166057.

It is an arithmetic number, because the mean of its divisors is an integer number (50565166057).

Almost surely, 2^101130332113 is an apocalyptic number.

It is an amenable number.

101130332113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130332113 is an equidigital number, since it uses as much as digits as its factorization.

101130332113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 101130332113 its reverse (311233031101), we get a palindrome (412363363214).

The spelling of 101130332113 in words is "one hundred one billion, one hundred thirty million, three hundred thirty-two thousand, one hundred thirteen".