1011304011703 has 2 divisors, whose sum is σ = 1011304011704. Its totient is φ = 1011304011702.

The previous prime is 1011304011691. The next prime is 1011304011719. The reversal of 1011304011703 is 3071104031101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011304011703 - 2²⁹ = 1010767140791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011304015703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505652005851 + 505652005852.

It is an arithmetic number, because the mean of its divisors is an integer number (505652005852).

Almost surely, 2^{1011304011703} is an apocalyptic number.

1011304011703 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011304011703 is an equidigital number, since it uses as much as digits as its factorization.

1011304011703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 1011304011703 its reverse (3071104031101), we get a palindrome (4082408042804).

The spelling of 1011304011703 in words is "one trillion, eleven billion, three hundred four million, eleven thousand, seven hundred three".