Base | Representation |
---|---|
bin | 101111000101111011… |
… | …0001010100010011101 |
3 | 100200000221211122221221 |
4 | 1132023312022202131 |
5 | 3124103400323043 |
6 | 114243025053341 |
7 | 10210051615621 |
oct | 1361366124235 |
9 | 320027748857 |
10 | 101130479773 |
11 | 39986579304 |
12 | 17724487251 |
13 | 96c8aa289b |
14 | 4c75255181 |
15 | 296d5e18ed |
hex | 178bd8a89d |
101130479773 has 2 divisors, whose sum is σ = 101130479774. Its totient is φ = 101130479772.
The previous prime is 101130479711. The next prime is 101130479819. The reversal of 101130479773 is 377974031101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92146852249 + 8983627524 = 303557^2 + 94782^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101130479773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101130470773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565239886 + 50565239887.
It is an arithmetic number, because the mean of its divisors is an integer number (50565239887).
Almost surely, 2101130479773 is an apocalyptic number.
It is an amenable number.
101130479773 is a deficient number, since it is larger than the sum of its proper divisors (1).
101130479773 is an equidigital number, since it uses as much as digits as its factorization.
101130479773 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 111132, while the sum is 43.
The spelling of 101130479773 in words is "one hundred one billion, one hundred thirty million, four hundred seventy-nine thousand, seven hundred seventy-three".
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