10113110302147 has 2 divisors, whose sum is σ = 10113110302148. Its totient is φ = 10113110302146.

The previous prime is 10113110302067. The next prime is 10113110302193. The reversal of 10113110302147 is 74120301131101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10113110302147 - 2⁷ = 10113110302019 is a prime.

It is not a weakly prime, because it can be changed into another prime (10113110302247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056555151073 + 5056555151074.

It is an arithmetic number, because the mean of its divisors is an integer number (5056555151074).

Almost surely, 2^{10113110302147} is an apocalyptic number.

10113110302147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113110302147 is an equidigital number, since it uses as much as digits as its factorization.

10113110302147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 10113110302147 its reverse (74120301131101), we get a palindrome (84233411433248).

The spelling of 10113110302147 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred two thousand, one hundred forty-seven".