10113110312115 has 16 divisors (see below), whose sum is σ = 16182712320768. Its totient is φ = 5393080226016.

The previous prime is 10113110312099. The next prime is 10113110312131. The reversal of 10113110312115 is 51121301131101.

It is an interprime number because it is at equal distance from previous prime (10113110312099) and next prime (10113110312131).

It is not a de Polignac number, because 10113110312115 - 2⁴ = 10113110312099 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10113110312091 and 10113110312100.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36018439 + ... + 36298128.

It is an arithmetic number, because the mean of its divisors is an integer number (1011419520048).

Almost surely, 2^{10113110312115} is an apocalyptic number.

10113110312115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10113110312115 is a deficient number, since it is larger than the sum of its proper divisors (6069602008653).

10113110312115 is an equidigital number, since it uses as much as digits as its factorization.

10113110312115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72325898.

The product of its (nonzero) digits is 90, while the sum is 21.

Adding to 10113110312115 its reverse (51121301131101), we get a palindrome (61234411443216).

The spelling of 10113110312115 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred fifteen".