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10113110312099 is a prime number
BaseRepresentation
bin1001001100101010010001…
…0110010000010010100011
31022210210201001020110021212
42103022210112100102203
52311143122214441344
633301522043340335
72062435205212124
oct223124426202243
938723631213255
1010113110312099
113249a451396a3
121173ba42216ab
1358487bb51092
1426d69743204b
151280ea11e79e
hex932a45904a3

10113110312099 has 2 divisors, whose sum is σ = 10113110312100. Its totient is φ = 10113110312098.

The previous prime is 10113110312077. The next prime is 10113110312131. The reversal of 10113110312099 is 99021301131101.

It is a happy number.

It is an a-pointer prime, because the next prime (10113110312131) can be obtained adding 10113110312099 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10113110312099 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (10113110312009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056555156049 + 5056555156050.

It is an arithmetic number, because the mean of its divisors is an integer number (5056555156050).

Almost surely, 210113110312099 is an apocalyptic number.

10113110312099 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113110312099 is an equidigital number, since it uses as much as digits as its factorization.

10113110312099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 32.

The spelling of 10113110312099 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, ninety-nine".