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10113110312114 = 28775765741341
BaseRepresentation
bin1001001100101010010001…
…0110010000010010110010
31022210210201001020110022102
42103022210112100102302
52311143122214441424
633301522043340402
72062435205212145
oct223124426202262
938723631213272
1010113110312114
113249a45139707
121173ba4221702
1358487bb510a4
1426d69743205c
151280ea11e7ae
hex932a45904b2

10113110312114 has 8 divisors (see below), whose sum is σ = 15186962694828. Its totient is φ = 5050789413840.

The previous prime is 10113110312099. The next prime is 10113110312131. The reversal of 10113110312114 is 41121301131101.

It can be written as a sum of positive squares in 2 ways, for example, as 8137070028025 + 1976040284089 = 2852555^2 + 1405717^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×101131103121143 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2882868917 + ... + 2882872424.

Almost surely, 210113110312114 is an apocalyptic number.

10113110312114 is a deficient number, since it is larger than the sum of its proper divisors (5073852382714).

10113110312114 is an equidigital number, since it uses as much as digits as its factorization.

10113110312114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5765742220.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 10113110312114 its reverse (41121301131101), we get a palindrome (51234411443215).

The spelling of 10113110312114 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 877 1754 5765741341 11531482682 5056555156057 10113110312114