Base | Representation |
---|---|
bin | 1001001100101010010001… |
… | …0110010000010010110010 |
3 | 1022210210201001020110022102 |
4 | 2103022210112100102302 |
5 | 2311143122214441424 |
6 | 33301522043340402 |
7 | 2062435205212145 |
oct | 223124426202262 |
9 | 38723631213272 |
10 | 10113110312114 |
11 | 3249a45139707 |
12 | 1173ba4221702 |
13 | 58487bb510a4 |
14 | 26d69743205c |
15 | 1280ea11e7ae |
hex | 932a45904b2 |
10113110312114 has 8 divisors (see below), whose sum is σ = 15186962694828. Its totient is φ = 5050789413840.
The previous prime is 10113110312099. The next prime is 10113110312131. The reversal of 10113110312114 is 41121301131101.
It can be written as a sum of positive squares in 2 ways, for example, as 8137070028025 + 1976040284089 = 2852555^2 + 1405717^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×101131103121143 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2882868917 + ... + 2882872424.
Almost surely, 210113110312114 is an apocalyptic number.
10113110312114 is a deficient number, since it is larger than the sum of its proper divisors (5073852382714).
10113110312114 is an equidigital number, since it uses as much as digits as its factorization.
10113110312114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5765742220.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 10113110312114 its reverse (41121301131101), we get a palindrome (51234411443215).
The spelling of 10113110312114 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred fourteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •