10113110312131 has 2 divisors, whose sum is σ = 10113110312132. Its totient is φ = 10113110312130.

The previous prime is 10113110312099. The next prime is 10113110312197. The reversal of 10113110312131 is 13121301131101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113110312131 - 2⁵ = 10113110312099 is a prime.

It is a super-2 number, since 2×10113110312131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10113110312099 and 10113110312108.

It is not a weakly prime, because it can be changed into another prime (10113113312131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056555156065 + 5056555156066.

It is an arithmetic number, because the mean of its divisors is an integer number (5056555156066).

Almost surely, 2^{10113110312131} is an apocalyptic number.

10113110312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113110312131 is an equidigital number, since it uses as much as digits as its factorization.

10113110312131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10113110312131 its reverse (13121301131101), we get a palindrome (23234411443232).

The spelling of 10113110312131 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred thirty-one".