10113120211 has 2 divisors, whose sum is σ = 10113120212. Its totient is φ = 10113120210.

The previous prime is 10113120179. The next prime is 10113120271. The reversal of 10113120211 is 11202131101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113120211 - 2⁵ = 10113120179 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10113120191 and 10113120200.

It is not a weakly prime, because it can be changed into another prime (10113120271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056560105 + 5056560106.

It is an arithmetic number, because the mean of its divisors is an integer number (5056560106).

Almost surely, 2^10113120211 is an apocalyptic number.

10113120211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113120211 is an equidigital number, since it uses as much as digits as its factorization.

10113120211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10113120211 its reverse (11202131101), we get a palindrome (21315251312).

The spelling of 10113120211 in words is "ten billion, one hundred thirteen million, one hundred twenty thousand, two hundred eleven".