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10113123212303 is a prime number
BaseRepresentation
bin1001001100101010010100…
…0111011101110000001111
31022210210201221111212001012
42103022211013131300033
52311143134020243203
633301523224035435
72062435422651056
oct223124507356017
938723657455035
1010113123212303
113249a5144a821
121173ba8602b7b
13584881719a37
1426d69902d39d
151280eb31bbd8
hex932a51ddc0f

10113123212303 has 2 divisors, whose sum is σ = 10113123212304. Its totient is φ = 10113123212302.

The previous prime is 10113123212273. The next prime is 10113123212323. The reversal of 10113123212303 is 30321232131101.

10113123212303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10113123212303 - 26 = 10113123212239 is a prime.

It is a super-2 number, since 2×101131232123032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113123212323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056561606151 + 5056561606152.

It is an arithmetic number, because the mean of its divisors is an integer number (5056561606152).

Almost surely, 210113123212303 is an apocalyptic number.

10113123212303 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113123212303 is an equidigital number, since it uses as much as digits as its factorization.

10113123212303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 10113123212303 its reverse (30321232131101), we get a palindrome (40434355343404).

The spelling of 10113123212303 in words is "ten trillion, one hundred thirteen billion, one hundred twenty-three million, two hundred twelve thousand, three hundred three".