101131307 has 2 divisors, whose sum is σ = 101131308. Its totient is φ = 101131306.

The previous prime is 101131301. The next prime is 101131309. The reversal of 101131307 is 703131101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101131307 - 2¹⁰ = 101130283 is a prime.

Together with 101131309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101131301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565653 + 50565654.

It is an arithmetic number, because the mean of its divisors is an integer number (50565654).

Almost surely, 2^101131307 is an apocalyptic number.

101131307 is a deficient number, since it is larger than the sum of its proper divisors (1).

101131307 is an equidigital number, since it uses as much as digits as its factorization.

101131307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 101131307 is about 10056.4062666541. The cubic root of 101131307 is about 465.9026778900.

Adding to 101131307 its reverse (703131101), we get a palindrome (804262408).

The spelling of 101131307 in words is "one hundred one million, one hundred thirty-one thousand, three hundred seven".